Question

Area bounded by $y = x \sin x$ and $x -$axis between $x = 0$ and $x = 2 \pi$ is

• A. 0
• B. $2 \pi$ sq. unit
• C. $\pi$ sq. unit
• D. $4 \pi$ sq. unit

Answer 1

Answer: (D)

$4 \pi$ sq. unit

Answer 2

Required area is

$A _ { 1 } + A _ { 2 } = \int _ { 0 } ^ { \pi } y d x + \left| \int _ { \pi } ^ { 2 \pi } y d x \right| = 4 \pi$ sq.unit