Question

Area bounded by curve $y = k \sin x$between $x = \pi$ and $x = 2 \pi$ is

• A. $2 k$ sq. unit
• B. 0
• C. $\frac { k ^ { 2 } } { 2 }$ sq. unit
• D. $k$ sq. unit

Answer 1

Answer: (A)

$2 k$ sq. unit

Answer 2

Required area

$= k \int _ { \pi } ^ { 2 \pi } \sin x d x = k [ - \cos x ] _ { \pi } ^ { 2 \pi } = - 2 k$

Hence, area = 2k sq. unit.