QuestionReportMathematics Question on Area under Simple CurvesArea bounded by 0≤y≤min(x2+2,2x+2)0 ≤ y ≤ \text {min}(x^2+ 2, 2x + 2)0≤y≤min(x2+2,2x+2), x∈[0,3]x∈[0, 3]x∈[0,3], then 12A12A12A isAnswerThe answer is 164.