Question

$[Ar]^{18} 3d^{10}4s^1$ electronic configuration belongs to

• A. Ti
• B. Tl
• C. Cu
• D. V

Answer 1

Answer: (C)

Cu

Answer 2

$\bar{v} = R (\frac{1}{n_1^2} - \frac{1}{n_2^2})Z^2$ $= R(\frac{1}{1^2} - \frac{1}{2^2})\times 3$ $= R [\frac{4-3}{4}]\times 3^2$ $= \frac{27R}{4}$ $\lambda = \frac{1}{\bar{v}}$ $=\frac{4}{27 R}$