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Question: Aqueous sulphuric acid reacts with 2-methyl-1-butene to give predominantly....

Aqueous sulphuric acid reacts with 2-methyl-1-butene to give predominantly.

A

Isobutyl hydrogen sulphate

B

2-methyl-2-butanol

C

2-methyl-1-butanol

D

Secondary butyl hydrogen sulphate

Answer

2-methyl-2-butanol

Explanation

Solution

CH3CH2=CCH2CH32methyl-1-butane+H2OH2SO4Markownikoff’s rule\begin{matrix} CH_{3} \\ C ⥂ \underset{2 - \text{methyl-1-butane}}{H_{2} = \overset{|}{C} - CH_{2} - CH_{3}} + H_{2}O\underset{\text{Markownikoff's rule}}{\overset{\quad H_{2}SO_{4}\quad}{\rightarrow}} \end{matrix}

6mu6mu6mu6mu6mu6mu6muCH3CH3CCH2CH36mu6mu6mu6mu6mu6mu6mu6muOH2Methyl-2-butanol\underset{2 - \text{Methyl-2-butanol}}{\begin{matrix} \mspace{6mu}\mspace{6mu}\mspace{6mu}\mspace{6mu}\mspace{6mu}\mspace{6mu}\mspace{6mu} CH_{3} \\ CH_{3} - \overset{\underset{|}{|}}{C} - CH_{2} - CH_{3} \\ \mspace{6mu}\mspace{6mu}\mspace{6mu}\mspace{6mu}\mspace{6mu}\mspace{6mu}\mspace{6mu}\mspace{6mu} OH \end{matrix}}