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Question: Aqueous solution of two compounds M<sub>1</sub>–O–H and M<sub>2</sub>–O–H are prepared in two differ...

Aqueous solution of two compounds M1–O–H and M2–O–H are prepared in two different beakers. If the electronegativity of M1 = 3.4 , M2 = 1.2, O = 3.5 and H = 2.1, then the nature of two solution will be respectively –

A

Acidic, basic

B

Acidic, acidic

C

Basic, acidic

D

Basic, basic

Answer

Acidic, basic

Explanation

Solution

The electronegatively difference between M1 and O is 0.1. Which indicates M1 – O bond will be covalent, O – H bond having more ionic character will break and H+ ions will release, and acidic solution is formed. Where as difference between electronegativity of M2 and O bond is 2.3 thus M2 – OH bond will break. Hence the solution will be basic in nature.

Hence (1) is correct.