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Question: Aqueous solution of \[\;N{H_4}Cl\] is in………. nature due to the behavior of ion……. in solution. A...

Aqueous solution of   NH4Cl\;N{H_4}Cl is in………. nature due to the behavior of ion……. in
solution.
A. An acidic;   NH4+\;N{H_4}^ +
B. alkaline;   NH4+\;N{H_4}^ +
C. acidic   Cl\;C{l^ - }
D. alkaline   Cl\;C{l^ - }

Explanation

Solution

Chemical formula is a way to write a substance using the chemical symbol and number subscripts to mention the number of the atoms into that chemical compound. Ammonium chloride is an inorganic salt. The formula of ammonium chloride is NH4ClN{H_4}Cl .

Complete step by step answer:
The aqueous solution of aluminum chloride is a salt of the weak acid and strong hydrochloride salt, the reaction is shown below,
HCl+NH4OHNH4Cl+H2OHCl\, + N{H_4}OH \to N{H_4}Cl + {H_2}O
Therefore, in water Ammonium chloride forms NH4+N{H_4}^ + ions. Which can accept hydroxyl ions from water and produce hydrogen ions to make the solution acidic. The reaction is shown below,

\;N{H_4}^ + + C{l^ - } + {H_2}O \rightleftharpoons N{H_4}OH + {H^ + } + C{l^ - } \\\ \;N{H_4}^ + + {H_2}O \rightleftharpoons N{H_4}OH + {H^ + } \\\\$$ So, the Aqueous solution of $$\;N{H_4}Cl$$ is acidic in nature due to the behavior of ion $$\;N{H_4}^ +$$ in the solution. **So, the correct option is, A.** **Additional information:** On the reaction of Ammonium chloride with NaOH, it forms salt sodium chloride, water, and ammonia.The reaction is shown below. $$N{H_4}Cl + NaOH\xrightarrow{{Heat}}NaCl + N{H_{3}} + {H_{2}}O$$ When ammonium chloride reacts with slaked lime or calcium hydroxide, ammonia gas is evolved with its characteristic pungent odor. Calcium hydroxide is a stronger base and thus displaces ammonia which is a weaker base from the ammonium chloride salt. From this, we can conclude that any alkali can displace ammonia from ammonium salts.Along with ammonia, two more products are formed. These are calcium chloride and water molecules.Now we know the reactants used and products formed in this chemical reaction, so we can balance the chemical equation by counting and equalizing the number of atoms of each species involved on both sides of an arrow. $$2N{H_4}Cl + Ca{(OH)_2} \to 2N{H_3} + CaC{l_2} + 2{H_2}O$$ **Note:** According to the law of conservation of mass, in an isolated system, mass is neither created nor destroyed by any chemical or physical transformations.A chemical equation represents the substances that are involved in a chemical reaction i.e. reactants and products. The balanced chemical equation is the one that has the same number of atoms on both sides of a reaction.