Question

Aqueous solution of $KCl$ is _____.
A. Acidic
B. Basic
C. Neutral
D. None of the above

Answer 1

-Salts of strong bases and strong acids: pH will remain neutral at $7$.
-Salts of weak bases and strong acids: pH less than $7$ (acidic).
-Salts of strong bases and weak acids: pH more than $7$ (basic).

Complete answer:
-The ions from $KCl$ derived from a strong acid (HCl) and a strong base (KOH). Therefore, neither ion will affect the acidity of the solution so, $KCl$ is a neutral salt.
-Reactions involved for the derivation of $KCl$ : $KOH + HCl \to KCl + {H_2}O\left( l \right)$;from here we are able to understand that $KCl$ is neutral as its reaction involved strong base and strong acid and making each other’s reaction equitable so the aqueous solution formed is neutral because its pH is approximately $7.$
-In the same way we can prove that aqueous solutions of others salts like $NaCl,KN{O_2},N{H_4}Br$ , etc. are neutral, basic or neutral.
-For example:$NaOH + HCl \to NaCl + {H_2}O\left( l \right)$ ;here, $NaOH$ is a strong base and $HCl$is a strong acid therefore aqueous solution of NaCl is also neutral because its pH is approximately $7$
-Similarly for $KN{O_2}$ , $KN{O_2}$ is basic salt as its ${K^ + }$ ions derives from a strong base and $N{O_2}$.
-Ion is derived from a weak acid $\left( {N{O_2}} \right)$.Therefore, its pH becomes more than $7$.
So, the correct answer is “Option C”.

Note:
Potassium chloride is a metal halide salt composed of potassium and chlorine it is odorless and has a white or colorless vitreous crystal appearance. The solid dissolves readily in water and its solutions have a taste just like salt.