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Question: Approximately how many moles of potassium permanganate, \(KMn{{O}_{4}}\), are present in 40g of this...

Approximately how many moles of potassium permanganate, KMnO4KMn{{O}_{4}}, are present in 40g of this compound? (Atomic weights: K=39; Mn=55; O=16)
(A) 1 mole
(B) 0.5 mole
(C) 0.25 mole
(D) 0.1 mole

Explanation

Solution

Moles is the amount of substance present in any compound. Molar mass can be calculated by the sum of individual masses of the atom present in the compound. Moles of a compound or atom can be found using weight, molecular weight etc.

Complete step by step solution:
The mole (symbol- mol) is the unit of measurement for the amount of substance in the International System of Units (SI).
The formula of moles to be used is:
mole=weightmolecular weightmole=\dfrac{weight}{\text{molecular weight}}
Molecular weight of KMnO4KMn{{O}_{4}} is [39+65+(16x4)]=[39+65+(16x4)] = 158grams158grams.
158g of KMnO4KMn{{O}_{4}} contains 55grams of Potassium (atomic weight of potassium is 55grams)
Therefore, 40g of KMnO4KMn{{O}_{4}} contains 55158×40\dfrac{55}{158}\times 40, which is equal to 14 grams of potassium.
55 grams of potassium equal to 1 mole of potassium, therefore, 1gram of potassium equals 155\dfrac{1}{55}mole of potassium.
Thus, 14grams of potassium equals 155×14\dfrac{1}{55}\times 14mole of potassium, which is equal to 0.25 mole of potassium.

Therefore, the correct answer is the (C) option.

Note: A mole of a substance or a mole of particles is defined as exactly 6.02214076×1023 6.02214076\times {{10}^{23}}~ particles, which may be atoms, molecules, ions, or electrons. In short, for particles 1 mol = 6.02214076×1023 6.02214076\times {{10}^{23}}~. The molar mass of a substance is the mass of 1 mole of that substance, in multiples of the gram. The amount of substance is the number of moles in the sample.