Question

Aniline is reacted with bromine water and the resulting product is treated with an aqueous solution of sodium nitrite in presence of dilute hydrochloric acid. The compound so formed is converted into a tetrafluoroborate which is subsequently heated. The final product is

• A. 1,3, 5-tribromobenzene
• B. p-bromofluorobenzene
• C. p-bromoaniline
• D. 2, 4, 6-tribromofluorobenzene

Answer 1

Answer: (D)

2, 4, 6-tribromofluorobenzene

Answer 2

The correct answer is D:2, 4, 6-tribromofluorobenzene
-$NH_2$ group is greatly activating group. Hence, reaction takes place rapidly.