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Question

Quantitative Aptitude Question on SI & CI

Anil invests Rs 22000 for 6 years in a scheme with 4% interest per annum, compounded half-yearly. Separately, Sunil invests a certain amount in the same scheme for 5 years, and then reinvests the entire amount he receives at the end of 5 years, for one year at 10% simple interest. If the amounts received by both at the end of 6 years are equal, then the initial investment, in rupees, made by Sunil is

A

20640

B

20808

C

20860

D

20480

Answer

20808

Explanation

Solution

Anil's Investment: Principal = Rs 22000 Rate of interest = 4 percent per annum compounded half-yearly = 2 percent per half-year Time = 6 years = 12 half-years The formula for the amount is:

Amount = Principal × (1+Rate100)Time(1 + \frac{Rate}{100})^{Time}

Substituting the given values:

Amount = 22000 × (1+2100)12(1 + \frac{2}{100})^{12} ≈ 27816.22

Sunil's Investment: Let the initial investment be P. After 5 years at 4 percent compounded half-yearly, the amount becomes:

This amount is then reinvested for 1 year at 10 percent simple interest. So, the final amount for Sunil = P(1+2100)10(1+10100)P \left( 1 + \frac{2}{100} \right)^{10} \left( 1 + \frac{10}{100} \right)

Given that both amounts are equal: 27816.22=P(1+2100)10(1+10100)27816.22 = P \left( 1 + \frac{2}{100} \right)^{10} \left( 1 + \frac{10}{100} \right)

Solving for P, we get P20808P \approx 20808

Therefore, Sunil's initial investment was approximately Rs 20808.