Question

Angular velocity of minute hand of a clock is

• A. $\frac{\pi}{30} rad\,s^{-1}$
• B. $\pi\,rad\,s^{-1}$
• C. $2\pi\,rad\,s^{-1}$
• D. $\frac{\pi}{1800} rad\,s^{-1}$

Answer 1

Answer: (D)

$\frac{\pi}{1800} rad\,s^{-1}$

Answer 2

The correct answer is Option D) $\frac{\pi}{1800} rad\,s^{-1}$

The minute hand of a clock rotates through an angle of 2$\pi$ in 60 min

1 hr = 60 min = 3600 sec

According to the formula, angular velocity (ω) = position angle (θ) / time (t)

Therefore, Angular velocity ω = θ​/t = 2 π ​ / 3600 =π ​ / 1800 rads −1

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