Solveeit Logo
Login

Question

Physics Question on Motion in a plane

Angular velocity of hour hand of a watch is

A

π43200rads−1\frac{\pi}{43200}rads^{-1}

B

π30rads−1\frac{\pi}{30}rads^{-1}

C

π21600rads−1\frac{\pi}{21600}rads^{-1}

D

π1800rads−1\frac{\pi}{1800}rads^{-1}

Answer

π21600rads−1\frac{\pi}{21600}rads^{-1}

Explanation

Solution

Angular velocity = angle tracedtime taken\frac{angle\, traced }{ time \,taken}

Time period of hour hand is 12 h .
So, ω=2π12rad h−1\omega = \frac{2\pi}{12} rad\,h^{-1}
= 2π12×60×60rad s−1=π21600rad s−1\frac{2\pi}{12 \times 60 \times 60}rad\,s^{-1} = \frac{\pi}{21600}rad\,s^{-1}