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Question

Physics Question on Atoms

Angular momentum of an electron in an orbit of H atom is proportional to

A

rr

B

1r\frac{1}{r}

C

r\sqrt{r}

D

1r \frac{1}{\sqrt{r}}

Answer

r\sqrt{r}

Explanation

Solution

Angular momentum of an electron in an orbit of H-atom
L=nh2πL = \frac{nh}{2 \pi }
Also , rn2Zr \propto \frac{n^2}{Z}
So, LrL \propto \sqrt{r}