Question

Angular frequency of an electron in Bohr atom with quantum number n is proportional to

• A. $n$
• B. $n^2$
• C. $n^3$
• D. $\frac{1}{n^3}$

Answer 1

Answer: (D)

$\frac{1}{n^3}$

Answer 2

Angular frequency , $\omega_n = \frac{v_n}{r_n}$
Also, $r_n \propto n^2$ and $v_n \propto \frac{1}{n}$
So, $\omega_n \propto \frac{1}{n^3}$