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Question

Mathematics Question on Right-Angled Triangles And Pythagoras Property

Angles QQ and RR of a ΔΔ PQRPQR are 25°25° and 65°65°. Write which of the following is true:

  1. PQ2+QR2=RP2PQ^2 + QR^2= RP^2
  2. PQ2+RP2=QR2PQ^2 + RP^2= QR^2
  3. RP2+QR2=PQ2RP^2 + QR^2= PQ^2

triangle PQR

Answer

The sum of the measures of all interior angles of a triangle is 180180\degree.

PQR+PRQ+QPR=180\angle PQR + \angle PRQ + \angle QPR = 180\degree

25+65+QPR=18025\degree + 65\degree + \angle QPR = 180\degree

90+QPR=18090\degree + \angle QPR = 180\degree

QPR=18090=90\angle QPR = 180\degree - 90\degree = 90\degree

Therefore, ΔΔ PQRPQR is right-angled at point PP.

Hence, (PR)2+(PQ)2=(QR)2(PR)^2 + (PQ)^2= (QR)^2
triangle RPQ

Thus,(ii) is true.