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Question: Angle of glass prism is 60<sup>0</sup> and refractive index of the material of the prism is 1.414,th...

Angle of glass prism is 600 and refractive index of the material of the prism is 1.414,then what will be the angle of incidence, so that ray should pass symmetrically through prism

A

380 61'

B

350 35'

C

450

D

530 8'

Answer

450

Explanation

Solution

Incident ray and emergent ray are symmetrical in the cure, when prism is in minimum deviation position.

Hence in this condition \Rightarrow sini=μsin(A2)\sin i = \mu \sin \left( \frac { A } { 2 } \right)

\Rightarrow sini=1.414×sin30=12i=45\sin i = 1.414 \times \sin 30 ^ { \circ } = \frac { 1 } { \sqrt { 2 } } \Rightarrow i = 45 ^ { \circ }