Question

Angle of banking for a vehicle speed of $10\,m/s$ for a radius of curvature $10\,m$ is (assume $g=10\,m/s^{2}$ )

• A. $30^{\circ}$
• B. $\tan^{-1}\left( \frac{1}{2} \right)$
• C. $60^{\circ}$
• D. $45^{\circ}$

Answer 1

Answer: (D)

$45^{\circ}$

Answer 2

Angle of banking is given by $\tan \theta=\frac{v^{2}}{r g}$
where $v$ is velocity, $r$ the radius of circular path and $g$ acceleration due to gravity. Given,
$v=10 \,m / s , r=10 \,m , g=10 \,m / s ^{2}$
$\therefore \tan \theta=\frac{10 \times 10}{10 \times 10}=1$
$\Rightarrow \theta=45^{\circ}$