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Question: Angle between the lines represented by the equation \(x^{2} + 2xy\sec\theta + y^{2} = 0\) is...

Angle between the lines represented by the equation x2+2xysecθ+y2=0x^{2} + 2xy\sec\theta + y^{2} = 0 is

A

θ\theta

B

2θ2\theta

C

θ2\frac{\theta}{2}

D

None of these

Answer

θ\theta

Explanation

Solution

Let angle between both the lines is α\alpha, then

α=tan1(2h2aba+b)=tan1(2sec2θ11+1)=θ\alpha = \tan^{- 1}\left( \frac{2\sqrt{h^{2} - ab}}{a + b} \right) = \tan^{- 1}\left( \frac{2\sqrt{\sec^{2}\theta - 1}}{1 + 1} \right) = \theta .