Question

Angle between lines 2x = 3y = – z and 6x = – y = – 4z is

• A. 0⁰
• B. 30⁰
• C. 45⁰
• D. 90⁰

Answer 1

Answer: (B)

30⁰

Answer 2

$\frac{x}{3} = \frac{y}{2} = \frac{z}{- 6}$ and $\frac{x}{2} = \frac{y}{- 12} = \frac{z}{- 3}$

\ cos q = $\frac{3(2) + 2( - 12) + ( - 6)( - 3)}{\sqrt{9 + 4 + 36}\sqrt{4 + 144 + 9}}$

cos q = 0

\ q = 90⁰