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Question: An urn contains 4 white and 3 red balls. Three balls are drawn with replacement from this urn. Then,...

An urn contains 4 white and 3 red balls. Three balls are drawn with replacement from this urn. Then, the standard deviation of the number of red ball drawn is
A.67\dfrac{6}{7}
B.3649\dfrac{36}{49}
C.57\dfrac{5}{7}
D.2549\dfrac{25}{49}

Explanation

Solution

Hint : The variance of XX is the arithmetic mean of the squares of all deviations of XX from the arithmetic mean of the observations and it is denoted by Var(X)Var(X) or σ2\sigma _{{}}^{2}. The position square root of the variance of XX is known as the standard deviation and it is denoted by σ\sigma .
Standard deviation =67=\dfrac{6}{7}
To find the standard deviation first variance has to be found. Variance can be calculated using the formula given below
Var(X)=1ni=1nxi2(1ni=1nxi)2Var(X)=\dfrac{1}{n}\sum\limits_{i=1}^{n}{x_{i}^{2}}-{{\left( \dfrac{1}{n}\sum\limits_{i=1}^{n}{{{x}_{i}}} \right)}^{2}}

Complete step-by-step answer :
Let us assume that XXis the number of red balls.
The probability of getting red ball is 37\dfrac{3}{7} and the probability of getting white ball is 47\dfrac{4}{7}
Using the Binomial distribution concept to solve
Here nn is the number of red balls and pp is the probability of getting the red balls and qq is the probability of not getting the red balls.
By observing we get
n=3n=3
p=37p=\dfrac{3}{7}
And q=47q=\dfrac{4}{7}
In Binomial distribution,
Mean=npMean=np
Variance=npqVariance=npq
And Standard Deviation =npq=\sqrt{npq}
So after applying the values we get
Mean=3×37Mean=3\times \dfrac{3}{7}
Further solving we get the mean as
Mean=97Mean=\dfrac{9}{7}
For variance apply the value in the formula
Variance=3×37×47Variance=3\times \dfrac{3}{7}\times \dfrac{4}{7}
Further solving we get the variance as
Variance=3649Variance=\dfrac{36}{49}
For Standard Deviation use the formula npq\sqrt{npq}
Substituting the values we get
Standard Deviation =3649=\sqrt{\dfrac{36}{49}}
Further solving and simplifying we get
Standard Deviation =67=\dfrac{6}{7}
Therefore, the standard deviation is67\dfrac{6}{7}.
So, the correct answer is “Option A”.

Note : The mean deviation can also be used for calculation of variance and standard deviation. Compute the mean of the given observation and take the deviations of the observations from the mean. Square the deviation obtained and obtains the sum. Then, divide the sum. This will give the variance value.