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Question

Physics Question on Wave optics

An unpolarised beam of intensity I0I_{0} is incident on a pair of nicols making an angle of 6060^{\circ} with each other. The intensity of light emerging from the pair is

A

I0I_0

B

I02\frac{I_0}{2}

C

I04\frac{I_0}{4}

D

I08\frac{I_0}{8}

Answer

I04\frac{I_0}{4}

Explanation

Solution

According to Malus' law I=I0cos2θI =I_{0} \cos ^{2} \theta =I0(cos260)=I_{0}\left(\cos ^{2} 60^{\circ}\right) =I0×(12)2=I_{0} \times\left(\frac{1}{2}\right)^{2} =I04=\frac{I_{0}}{4}