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Question

Physics Question on electrostatic potential and capacitance

An uncharged parallel plate capacitor filled with a dielectric of dielectric constant KK is connected to an air filled identical parallel capacitor charged to potential V1V_1. If the common potential is V2V_2, the value of KK is

A

V1V2V1\frac{V_{1}-V_{2}}{V_{1}}

B

V1V1V2\frac{V_{1}}{V_{1}-V_{2}}

C

V2V1V2\frac{V_{2}}{V_{1}-V_{2}}

D

V1V2V2\frac{V_{1}-V_{2}}{V_{2}}

Answer

V1V2V2\frac{V_{1}-V_{2}}{V_{2}}

Explanation

Solution

Here,
V2=(CV1+0)(C+KC)V_{2} =\frac{\left(C V_{1}+0\right)}{(C+K C)}
V2=V11+KV_{2} =\frac{V_{1}}{1+K}
V2V1=11+K\frac{V_{2}}{V_{1}} =\frac{1}{1+K}
1+K=V1V21+K =\frac{V_{1}}{V_{2}}
K=V1V21K =\frac{V_{1}}{V_{2}}-1
k=V1V2V2k =\frac{V_{1}-V_{2}}{V_{2}}