An ultra violet photon and an electron have the same de-Brog... | PHYSICS - DE BROGLIE'S EXPLANATION OF BOHR'S SECOND POSTULATE OF QUANTISATION | SolveeIt | Solveeit

Today, August 19

Question

An ultra violet photon and an electron have the same de-Broglie wavelengths, then the energy of the photon is –

A

Greater than the KE of the electron

B

Less than the KE of the electron

C

Equal to the KE of the electron

D

None of these

Answer

Greater than the KE of the electron

Explanation

Solution

l_ph = l_e

$\frac{K.E_{e}}{K.E_{ph}}$ = $\frac{v}{2C}$ < 1

K.E_e < K.E_ph