Question

An organic compound X on treatment with acidified $\mathrm { K } _ { 2 } \mathrm { Cr } _ { 2 } \mathrm { O } _ { 7 }$ gives a compound Y which reacts with $I _ { 2 }$ and sodium carbonate to form tri-odomethane. The compound X is

• A. $\mathrm { CH } _ { 3 } \mathrm { OH }$
• B. $\mathrm { CH } _ { 3 } - \mathrm { CO } - \mathrm { CH } _ { 3 }$
• C. $\mathrm { CH } _ { 3 } \mathrm { CHO }$
• D. $\mathrm { CH } _ { 3 } \mathrm { CH } ( \mathrm { OH } ) \mathrm { CH } _ { 3 }$

Answer 1

Answer: (D)

$\mathrm { CH } _ { 3 } \mathrm { CH } ( \mathrm { OH } ) \mathrm { CH } _ { 3 }$

Answer 2