Question

An organic compound on combustion gives 0.22 g of CO2 and 0.126 g of H2O. If the percentage of C in given organic compound is 40%, the percentage of H will be?

Answer 1

The correct answer is 9.34%.

C%=$\frac{12}{44}\times \frac{0.22}{weight \,of\,sample}\times100$

$40=\frac{12}{44}\times \frac{0.22}{weight\,of\, sample}\times100$

$\therefore$ Weight of sample = $\frac{6}{40}=0.15g$

$\therefore$ H%=$\frac{2}{18}\times\frac{0.126}{0.15}\times 100$

= 9.34%