An organic compound on analysis gave (C = 54.2%, H = 9.2%)A... | Chemistry | SolveeIt | Solveeit

Today, August 18

Question

An organic compound on analysis gave $C = 54.2\%, H = 9.2\%$ A by mass. Its empirical formula is

A

$C H O_{2}$

B

$CH_{2}O$

C

$C_{2}H_{8}O$

D

$C_{2}H_{4}O$

Answer

$C_{2}H_{4}O$

Explanation

Solution

Empirical Formula $= C_{2}H_{4}O$