Question

An organic compound of molecular formula $C_{4}H_{10}O$ does not react with sodium. With excess of $HI$, it gives only one type of alkyl halide. The compound is

• A. ethoxyethane
• B. $1$ - butanol
• C. $1$ - methoxy propane
• D. $2$ - methoxypropane

Answer 1

Answer: (A)

ethoxyethane

Answer 2

Symmetrical ether (here ethoxyethane) gives only one type of halide with excess of $HI$. $\underset{\text{Ethoxyethane}}{ {C2H5OC2H5}}\,+ {2HI -> 2C2H5I +H2O}$