Question

An organic compound gave $0.4655g$ of $CO_{2}$ on complete combustion. If the the mass of the compound taken was $0.2115g,$ what is the percentage of C in it?

• A. $13.30\%$
• B. $26.67\%$
• C. $60.03\%$
• D. $28.80\%$

Answer 1

Answer: (C)

$60.03\%$

Answer 2

: Mass of $CO_{2}$ formed = $0.4655g$

Mass of organic compound taken = $0.2115g$

% of $C = \frac{12}{44} \times \frac{massofCO_{2}}{massofcompound} \times 100$

$= \frac{12}{44} \times \frac{0.4655}{0.2115} \times 100 = 60.03\%$