Question

An organic compound contains $78 \%$ (by wt.) carbon and remaining percentage of hydrogen. The right option for the empirical formula of this compound is: [Atomic wt. of $C$ is $12, H$ is $1$]

• A. $CH$
• B. $CH _{2}$
• C. $CH _{3}$
• D. $CH _{4}$

Answer 1

Answer: (C)

$CH _{3}$

Answer 2

$\% C =78$ $\% H =22$ $C : H =\frac{78}{12}: \frac{22}{1}$ $=6.5: 22$ $\frac{6.5}{6.5} : \frac{22}{6.5}=1: 3.3$ $C : H = CH _{3}$