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Question

Chemistry Question on Some basic concepts of chemistry

An organic compound contains 52.2%C52.2\%\, C and 13.04%H13.04\%\, H. Vapour density of the compound is 2323. Its molecular formula will be

A

C2H6OC_{2}H_{6}O

B

C5H10OC_{5}H_{10}O

C

C3H8OC_{3}H_{8}O

D

C4H8OC_{4}H_{8}O

Answer

C2H6OC_{2}H_{6}O

Explanation

Solution

Molecular weight =2×=2 \times Vapour density =2×23=46=2 \times 23=46 So, molecular formula =C2H6O=C_{2}H_{6}O