Solveeit Logo

Question

Question: An open vessel containing air is heated from \(300K\) to \(400K\). The fraction of air, which gives ...

An open vessel containing air is heated from 300K300K to 400K400K. The fraction of air, which gives out with respect to originally present is:
A. 34\dfrac{3}{4}
B. 14\dfrac{1}{4}
C. 23\dfrac{2}{3}
D. 18\dfrac{1}{8}

Explanation

Solution

You should know that the state of an amount of gas is determined by its pressure, volume and temperature. You can use the ideal gas equation for calculating this question. The temperature used in the equation of state is an absolute temperature who’s appropriate S.I. The unit is the kelvin.

Complete step by step solution:
Let us first know about the ideal gas law.
So, the ideal gas law which is also called the general gas equation, is the equation of state of a hypothetical ideal gas. It is often written in an empirical formula:
PV=nRTPV=nRT where,
P is the pressure,
V is the volume,
n is the amount of substance,
R is the ideal gas constant and
T is the temperature.
This equation is the same for all the gases.
So, here as the vessel is open, the pressure will remain constant. There is no change in the volume of the vessel. Thus, the volume will also remain constant. Since, pressure (P) and volume (V) are constant and R is already a universal constant therefore, the ideal equation can be written as:
n1n2=T2T1\dfrac{{{n}_{1}}}{{{n}_{2}}}=\dfrac{{{T}_{2}}}{{{T}_{1}}}
Where,
n1{{n}_{1}} is the initial number of moles,
n2{{n}_{2}} is the final number of moles,
T1{{T}_{1}} is the initial temperature and
T2{{T}_{2}} is the final temperature.
Here, T1{{T}_{1}} is 300K300\text{K} and T2{{T}_{2}} is 400K400\text{K} and let’s consider n1{{n}_{1}} be 11. So, the fraction of air present in the vessel will be:
1n2=T2T1\dfrac{1}{{{n}_{2}}}=\dfrac{{{T}_{2}}}{{{T}_{1}}}
Then, n2=T1T2{{n}_{2}}=\dfrac{{{T}_{1}}}{{{T}_{2}}}
Thus, n2=300400=34{{n}_{2}}=\dfrac{300}{400}=\dfrac{3}{4}
Therefore, the fraction of air present in the vessel is 34\dfrac{3}{4}. Therefore, the gas escaped out will be:
n1n2=134=14{{n}_{1}}-{{n}_{2}}=1-\dfrac{3}{4}=\dfrac{1}{4}

Hence, the correct option is B.

Note: Ideal gas law is a good approximation of the behaviour of many gases under many conditions, although it has several limitations. Generally, it is a combination of the empirical Boyle’s law, Charles’ law, Avogadro’s law and Gay-Lussac’s law.