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Question

Chemistry Question on States of matter

An open vessel containing air is heated from 27^\circC to 127^\circC. The fraction of air originally present which goes out of it is

A

44624

B

44565

C

44595

D

44569

Answer

44565

Explanation

Solution

V1T1=V2T2\frac{V_{1}}{T_{1}}=\frac{V_{2}}{T_{2}} initial fraction V1V2=1\frac{V_{1}}{V_{2}}=1 when temp. is 27C27^{\circ} C At 127C127^{*} C, the new fraction is V1V2=300400=34\frac{V_{1}}{V_{2}}=\frac{300}{400}=\frac{3}{4} \therefore Air expelled =134=14=1-\frac{3}{4}=\frac{1}{4}