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Question

Physics Question on Oscillations

An open pipe of length 33 cm resonates with frequency of 1000 Hz. If the speed of sound is 333ms1,333\,m{{s}^{-1}}, then this frequency is

A

fundamental frequency of the pipe

B

third harmonic of the pipe

C

second harmonic of the pipe

D

fourth harmonic of the pipe

Answer

second harmonic of the pipe

Explanation

Solution

1000 Hz = Frequency of p th harmonic =pV2l=p×3302×33=\frac{pV}{2l}=\frac{p\times 330}{2\times 33} =p×330×1002×33=\frac{p\times 330\times 100}{2\times 33} p=2p=2