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Question

Physics Question on Oscillations

An Open pipe and a closed pipe have same length. The ratio of pthp^{th} overtones of two pipes is

A

1p\frac{1}{p}

B

p

C

2(p+1)2p+1\frac{2(p+1)}{2p+1}

D

2p+12(p+1)\frac{2p+1}{2(p+1)}

Answer

2(p+1)2p+1\frac{2(p+1)}{2p+1}

Explanation

Solution

nopen=(p+1)V2L;nclosed=(2p+1)V4Ln_{open} = \frac{(p + 1)V}{2L} ; n_{closed} = \frac{(2p + 1) V}{4L}