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Question

Physics Question on work, energy and power

An open knife edge of mass m is dropped from a height hh on a wooden floor. If the blade penetrates distance ss into the wood, the average resistance offered by the wood to the blade is

A

mgmg

B

mg(hs)mg(\frac{h}{s})

C

mg(1hs)mg\left( 1-\frac{h}{s} \right)

D

mg(1+hs)2mg{\left( 1+\frac{h}{s} \right)}^{2}

Answer

mg(hs)mg(\frac{h}{s})

Explanation

Solution

Velocity at the time when knife edge strikes wooden floor is 2gh\sqrt{2gh} . The velocity of 2gh\sqrt{2gh} is reduced to zero in a distance ss. If FF is the average retardation, then by work-energy theorem, we have 012mv2=Fs0-\frac{1}{2}mv^{2}=-Fs \Rightarrow F=mghsF=mg\frac{h}{s}