Question
Question: An open flask contains air at \({{27}^{o}}C\). At what temperature should it be heated so that \(1/{...
An open flask contains air at 27oC. At what temperature should it be heated so that 1/3rdof air present in it goes out?
A. 177oC
B. 100oC
C. 300oC
D. 150oC
Solution
To solve this question, try to look at the parameters given to us in the question. Consider pressure, volume and real gas to be constant and relate the number of moles and temperature by using the ideal gas equation and you will get your answer.
Complete step by step solution:
According to the given question, there is an open flask that contains air at a temperature equal to 27oC i.e. equal to (27+273)K=300K and it is being asked to find out the temperature of the air so that 1/3rd amount is escaped.
So, we can say that there is a change in the number of moles of the air.
Thus, let us consider the initial number of moles of the air be N1 and the number of moles after one-third of the air goes out be N2.
The initial temperature be T1 i.e. 300Kand the temperature at which one-third of the gas goes out be T2.
So, N1=1 mole
Then, N2=N1−31=1−31=32
Considering volume(V), pressure(P) and real gas constant (R) to be constant and relating to the ideal gas equation i.e. PV=nRT, we can relate the number of moles(n) and temperature(T) as:
nT=Constant
So, here N1T1=N2T2.
Now, putting the values of moles and temperature, we will get:
1×300=32×T2
So, T2=2300×3=450K
Now, convert the temperature to Celsius.
So, T2=(450−273)oC=177oC
Therefore, the temperature should be heated at 177oC so that one-third of air present will go out.
Hence, the correct option is A.
Note: Ideal gas equation is the equation of state of an ideal gas (hypothetical). It is an approximation of the behaviour of gases under ideal conditions. It is a combination of empirical laws like Boyle’s law, Charles’ law, Gay-Lussac’s law and Avogadro’s law.