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Question: An observer moves towards a stationary source of sound of frequency n. The apparent frequency heard ...

An observer moves towards a stationary source of sound of frequency n. The apparent frequency heard by him is 2n. If the velocity of sound in air is 332 m/sec, then the velocity of the observer is

A

166 m/sec

B

664 m/sec

C

332 m/sec

D

1328 m/sec

Answer

332 m/sec

Explanation

Solution

n=n(v+vOv)2n=n(v+v0v)v+v0v=2n' = n\left( \frac{v + v_{O}}{v} \right) \Rightarrow 2n = n\left( \frac{v + v_{0}}{v} \right) \Rightarrow \frac{v + v_{0}}{v} = 2

\Rightarrow vO=v=332v_{O} = v = 332m/se