Question
Question: An observer \[1.5\] meters tall is \[20.5\] meters away from a tower \[22\] meters high. Determine t...
An observer 1.5 meters tall is 20.5 meters away from a tower 22 meters high. Determine the angle of elevation of the tower from the eye of the observer?
a)60∘
b)45∘
c)30∘
d)75∘ $$$$
Solution
Hint : We know trigonometric formulas like of cosθ=Hypotenusebase , sinθ=Hypotenuseperpendicular , tanθ=baseperpendicular .And values of, tan30∘=31 , tan45∘=1 , tan60∘=3 . The angle of elevation is the angle formed by the horizontal line of sight and the object when a person stands and looks up at it. The distance between the head and eye of a boy should be neglected.
Complete step-by-step answer :
We should know angle of elevation and angle of depression that is
The angle of elevation is the angle formed by the horizontal line of sight and the object when a person stands and looks up at it.
we should try to draw its diagrams,
And diagram for the following question is:
We have labelled diagram as:
Total height of pole is labelled as AC = height of pole
Height of boy is labelled as ED= height of boy
Distance between the boy and pole CD=distance between boy and pole
As line BE is parallel to CD and we know that distance between two parallel lines are always equal
Since ED =1.5, soBC=1.5
For calculating the length of AB
AB=AC-BC
AB=22−1.5
AB=20.5
From diagram, CD=BE
BE=20.5
And we know that tanθ=baseperpendicular
In triangle ABE
tanx=BEAB
tanx=20.520.5
tanx=1
And we know that tan45∘=1
So, angle of elevation is 45∘
So, the correct answer is “Option B”.
Note : The angle of elevation is the angle formed by the horizontal line of sight and the object when a person stands and looks up at it. The angle of depression is the angle between the horizontal line of sight and the object when a person stands and stares down at an item. If the problem that is to be solved is a right-angled triangle with an angle and a side known, trigonometric ratios can be used to find the remaining angles and sides.