Solveeit Logo

Question

Question: An observer \[1.5\] meters tall is \[20.5\] meters away from a tower \[22\] meters high. Determine t...

An observer 1.51.5 meters tall is 20.520.5 meters away from a tower 2222 meters high. Determine the angle of elevation of the tower from the eye of the observer?
a)60{60^ \circ }
b)45{45^ \circ }
c)30{30^ \circ }
d)75{75^ \circ } $$$$

Explanation

Solution

Hint : We know trigonometric formulas like of cosθ=baseHypotenuse\cos \theta = \dfrac{{base}}{{{\text{Hypotenuse}}}} , sinθ=perpendicularHypotenuse\sin \theta = \dfrac{{perpendicular}}{{{\text{Hypotenuse}}}} , tanθ=perpendicularbase\tan \theta = \dfrac{{perpendicular}}{{base}} .And values of, tan30=13\tan {30^ \circ } = \dfrac{1}{{\sqrt 3 }} , tan45=1\tan {45^ \circ } = 1 , tan60=3\tan {60^ \circ } = \sqrt 3 . The angle of elevation is the angle formed by the horizontal line of sight and the object when a person stands and looks up at it. The distance between the head and eye of a boy should be neglected.

Complete step-by-step answer :
We should know angle of elevation and angle of depression that is
The angle of elevation is the angle formed by the horizontal line of sight and the object when a person stands and looks up at it.
we should try to draw its diagrams,
And diagram for the following question is:

We have labelled diagram as:
Total height of pole is labelled as AC = height of pole
Height of boy is labelled as ED= height of boy
Distance between the boy and pole CD=distance between boy and pole
As line BE is parallel to CD and we know that distance between two parallel lines are always equal
Since ED =1.5ED{\text{ }} = 1.5, soBC=1.5BC = 1.5
For calculating the length of AB
AB=AC-BC
AB=221.5AB = 22 - 1.5
AB=20.5AB = 20.5
From diagram, CD=BE
BE=20.5
And we know that tanθ=perpendicularbase\tan \theta = \dfrac{{perpendicular}}{{base}}
In triangle ABE
tanx=ABBE\tan x = \dfrac{{AB}}{{BE}}
tanx=20.520.5\tan x = \dfrac{{20.5}}{{20.5}}
tanx=1\tan x = 1
And we know that tan45=1\tan {45^ \circ } = 1
So, angle of elevation is 45{45^ \circ }
So, the correct answer is “Option B”.

Note : The angle of elevation is the angle formed by the horizontal line of sight and the object when a person stands and looks up at it. The angle of depression is the angle between the horizontal line of sight and the object when a person stands and stares down at an item. If the problem that is to be solved is a right-angled triangle with an angle and a side known, trigonometric ratios can be used to find the remaining angles and sides.