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Physics Question on speed and velocity

An object of mass 'm' initially at rest on a smooth horizontal plane starts moving under the action of force F=2NF=2 N In the process of its linear motion, the angle θ\theta (as shown in figure) between the direction of force and horizontal varies as θ=kx\theta=k x, where kk is a constant and xx is the distance covered by the object from its initial position The expression of kinetic energy of the object will be E=nksinθE=\frac{n}{k} \sin \theta The valte of nn is

An object of mass m initially at rest on a smooth horizontal plane starts moving

Answer

An object of mass 'm' initially at rest on a smooth horizontal plane starts moving under the action of force F=2N