Question
Question: An object of mass \(2kg\) is dropped from a tower which hits the ground in \(10s\). Calculate the wo...
An object of mass 2kg is dropped from a tower which hits the ground in 10s. Calculate the work done
Solution
here in the question they have given the mass mthat is 2kgand they have also mentioned the time t that is 10sby using these two data we have to find the work done
As we know the work done can be defined as the transferring of energy from an object via the application of force along a displacement.
Complete step by step solution:
As we know the formulae for calculating the work done that is
W=Fs........(1)
Here Frepresent the force and srepresent the displacement
But in the question we have mass and time so first we have to find the value of force and displacement
So to find the value of force we have formulae
F=ma
Here mis the mass and arepresent the acceleration due to gravity
Hence we know the value of mthat is 2kgand the acceleration due to gravity is 9.8m/s2that is constant
F=2kg×9.8m/s2
After simplifying we get
F=19.6N
Now we have to calculate the value of displacement s
So we know the formulae to calculate the displacement that is
s=21at2
Here arepresent the acceleration due to gravity that is 9.8m/s2 and t is the time that is 10s
Now substitute the values in the above equation
s=21×9.8m/s2×10s
After simplifying the equation we get
s=49m/s
Now substitute the value of displacement sand the force Fin equation (1)
W=19.6×49
After calculating we get the value of work done
W=960.4N−m
Note: a force can be defined as the motion of an object. A force can cause an object with mass to change its velocity, force has both magnitude and direction
Displacement is a vector quantity whose length is the shortest distance from the initial to the final position .