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Question

Physics Question on Viscosity

An object of mass 26 kg floats in air and it is in equilibrium state. Air density is 1.3kg/m31.3 \,kg/m^3 . The volume of the object is :

A

26m3 26 \, m^3

B

10m3 10 \, m^3

C

20m3 20 \, m^3

D

13m3 13 \, m^3

Answer

20m3 20 \, m^3

Explanation

Solution

Given, mass of object (m)=26kg(m)=26 \,kg
Density of air (ρair )=1.3kg/m3\left(\rho_{\text {air }}\right)=1.3 \,kg / m ^{3}
The object is in equilibrium state.
So, mg=ρair Vgmg =\rho_{\text {air }}\, Vg
26g=1.3Vg26g =1.3 Vg
V=261.3V =\frac{26}{1.3}
V=20m3V =20 \,m ^{3}