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Question: An object of mass \(100\,kg\) is accelerated uniformly from a velocity of \(5\,m{s^{ - 1}}\) to \(8\...

An object of mass 100kg100\,kg is accelerated uniformly from a velocity of 5ms15\,m{s^{ - 1}} to 8ms18\,m{s^{ - 1}} in 6s6\,s . Calculate the initial and the final momentum of the object. Also, find the magnitude of the force exerted on the object.

Explanation

Solution

Hint
In order to calculate the value of the initial and the final momentum of the object, substitute the required values of mass and velocity in the below given formulae. Use these answers in the formula of force and also substitute the time taken to know the magnitude of the force.
(1) The momentum of the object is given by
Initial momentum= mumu
Where mm is the mass of the object and uu is the initial velocity of the object.
(2) Final momentum= mvmv
Where mm is the mass of the object and vv is the initial velocity of the object.
(3) The magnitude of the force is given by
F=Final momentum - initial momentumt\Rightarrow F = \dfrac{{{\text{Final momentum - initial momentum}}}}{t}
Where tt is the time taken for the movement and FF is the magnitude of the force exerted.

Complete step by step answer
The given data are
Mass of the object, m=100Kgm = 100\,Kg
Initial velocity of the object, u=5ms1u = 5\,m{s^{ - 1}}
Final velocity of the object, v=8ms1v = 8\,m{s^{ - 1}}
Time taken, t=6st = 6\,s
By using the formula of initial momentum,
Initial momentum= mumu
Substituting the values,
Initial momentum= 100×5100 \times 5
By doing the multiplication,
Initial momentum= 500Kgms1500\,Kgm{s^{ - 1}}.
Similarly the final momentum is calculated by the formula.
Final momentum= 100×8100 \times 8
Hence the final momentum of the object is 800Kgms1800\,Kgm{s^{ - 1}}.
In order to calculate the magnitude of the force, substitute the value of the initial momentum, final momentum and the time taken in its formula.
F=800 - 5006\Rightarrow F = \dfrac{{{\text{800 - 500}}}}{6}
F=3006\Rightarrow F = \dfrac{{300}}{6}
By performing division in the above step,
F=50N\Rightarrow F = 50\,N.

Hence the initial and the final momentum are 500Ns500\,Ns and 800Ns800\,Ns respectively. The magnitude of the force exerted by the object taken is 50N50\,N

Note
The momentum at the initial and the final condition differs, since the velocity of the object in those conditions changes. When the object begins to move, there is some force required to overcome the frictional force and to pick up the normal force, so the velocity at the starting is always less.