Question

An object O is placed at a distance of 100 cm in front of a concave mirror of radius of curvature 200 cm as shown in the figure. The object starts moving towards the mirror at a speed 2 cm/s. The position of the image from the mirror after 10 s will be at ____ cm.

Answer 1

The correct answer is 400
$After\ 10\ sec.$
$u = -80 cm$
$f = -100cm$
$\frac{1}{v} +\frac{1}{u} = \frac{1}{f}$
$v = 400cm$