Question

An object is thrown along a direction making an angle $45^{\circ}$ with the horizontal direction. The horizontal range of the object is equal to :

• A. twice the vertical height
• B. vertical height
• C. four times the vertical height
• D. three times of vertical height

Answer 1

Answer: (C)

four times the vertical height

Answer 2

We know that, for the calculation of vertical height $H =\frac{ v _{0}^{2} \sin 45^{\circ} R }{2 g }$ $R =4 H =4$ (The vertical height)