Question

An object is thrown along a direction inclined at an angle of 45º with the horizontal direction. The horizontal range of the particle is-

• A. Four times the vertical height
• B. Thrice the vertical height
• C. Twice the vertical height
• D. Equal to vertical heigh

Answer 1

Answer: (A)

Four times the vertical height

Answer 2

R = $\frac { \mathrm { u } ^ { 2 } } { \mathrm {~g} }$

H = $\frac { \mathrm { u } ^ { 2 } \sin ^ { 2 } 45 ^ { \circ } } { 2 \mathrm {~g} }$ = $\frac { u ^ { 2 } } { 4 \mathrm {~g} }$ = $\frac { \mathrm { R } } { 4 }$

R = 4H