Question

An object is projected with a speed 10 m/s at an angle of 30⁰ with the horizontal. The object breaks down into n equal fragments during its motion. One fragment is found to strike the ground at a distance of $\sqrt{3}$m from the point of projection in the same azimuthal plane, in which the object is projected. If the centre of mass of the remaining fragments strikes the ground at distance of 7$\sqrt{3}$ m from the point of projection, then the value of n is – (g = 10 m/s²)

• A. 2
• B. 3
• C. 4
• D. 525

Answer 1

Answer: (B)

3

Answer 2

R_cm = $\frac{10^{2}\sin 60}{g} = 5\sqrt{3}$

$5\sqrt{3}$ = $\frac{m\sqrt{3} + m(n - 1)7\sqrt{3}}{mn}$n = 3