Question

An object is projected in x-y plane from the origin at t=0 and its velocity changes according to relation $\bar{v} = a\hat{i}+bx\hat{j}$. Equation of path of particle is

• A. Hyperbolic
• B. Circular
• C. Elliptical
• D. Parabolic

Answer 1

Answer: (D)

Parabolic

Answer 2

$\frac{dx}{dt} = a, \therefore = at$ $\nu_y = bx = bat$ $\frac{dy}{dt} = bat , \int dy = \int bat \, dt$ $y = \frac{bat^2}{2}$ $y = \frac{bax^2}{2a} = \frac{bx^2}{2a}$ $y \alpha x^2$ i.e. parabolic