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Question

Physics Question on projectile motion

An object is projected in the air with initial velocity u at an angle θ. The projectile motion is such that the horizontal range R, is maximum. Another object is projected in the air with a horizontal range half of the range of first object. The initial velocity remains same in both the case. The value of the angle of projection, at which the second object is projected, will be ______ degree.

Answer

θ=45\theta = 45^\circ
R1=R2R_1=\frac{R}{2}
u2sin2θ1g=u2sin(90)2g\frac{u^2 \sin^2 \theta_1}{g} = \frac{u^2 \sin(90^\circ)}{2g}
2θ1=302\theta_1 = 30^\circ
θ1=15\theta_1 = 15^\circ
So, the answer is 15°