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Question

Physics Question on Ray optics and optical instruments

An object is placed at 20cm20\,cm in front of a concave mirror produces three times magnified real image. What is focal length of the concave mirror ?

A

15 cm

B

6.6 cm

C

10 cm

D

7.5 cm

Answer

15 cm

Explanation

Solution

We know that
Linear magnification m=ffum=\frac{f}{f-u}
Given, object displaced u=20cmu=-20 \,cm
m=3m=-3
((\because all real image are inverted)
So, 3=ff(20)-3=\frac{f}{f-(-20)}
3=ff+20-3=\frac{f}{f+20}
3f60=f\Rightarrow-3 f-60=f
4f=604 f=-60
f=604=15cm\Rightarrow f=-\frac{60}{4}=-15 cm
Since, mirror is concave f=15cmf=-15 \,cm.